Loi de Stefan-Boltzmann

How to use it

1. Temperature T = 500 K, surface A = 2.m², emissivity ε = 0.85
2. Calculate T⁴ = 500⁴ = 6.25×10¹â°
3. Multiply: σ × ε × A × T⁴
4. P = 5.670374×10⁻⁸ × 0.85 × 2.5 × 6.25×10¹â° ≈ 7533.16 W

Common mistakes

• ⚠️ Using Celsius instead of Kelvin (must be absolute temperature)
• ⚠️ Forgetting emissivity facteur (assumes blackbody)
• ⚠️ Wrong power of temperature (must be T⁴)

Worked example

Find radiated power from a 2.m² surface at 500 K with emissivity 0.85.

The radiated power {power} W is emitted according to the Stefan-Boltzmann law.

Input guide