Loi des Gaz Parfaits
Last updated: 2026-08-24
Loi des Gaz Parfaits — Calculez la variable inconnue de la loi des gaz parfaits.
Inputs
Result
Enter values and press Calculate
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How to use it
- Given: P=202650 Pa, V=0.m³, n=1.mol, T=0 (unknown)
- Rearrange: T = PV ÷ (nR)
- Calculate: T = (202650 × 0.015) ÷ (1.2 × 8.314)
- T = 3039.÷ 9.9768 ≈ 304.68 K
Common mistakes
- ⚠️ Not setting exactly one variable to for solving
- ⚠️ Using wrong value for gas constant R
- ⚠️ Using Celsius instead of Kelvin for temperature
Worked example
Find the missing variable (T=0) in ideal gas law with P=202650 Pa, V=0.m³, n=1.mol.
The missing variable is calculeted: {missing} using PV = nRT where R = 8.314 J/(mol·K).
Input guide
| Field | Typical range |
|---|---|
| P | Pressure: 100 to 1e8 Pa |
| T | Temperature: 1 to 5000 K (use 0 for unknown) |
| V | Volume: 0.0001 to 100 m³ |
| n | Moles: 0.001 to 1000 mol |