COP EER Calculator
Last updated: 2026-08-10
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| Useful thermal output (kW) (kW útil) | Electrical power consumed (kW) (kW eléctrico) | |
|---|---|---|
| Small room | 1.75 kW útil | 0.5 kW eléctrico |
| Medium room | 2.625 kW útil | 0.75 kW eléctrico |
| Large room | 3.5 kW útil | 1 kW eléctrico |
| Office | 5.25 kW útil | 1.5 kW eléctrico |
| Warehouse | 7 kW útil | 2 kW eléctrico |
The COP EER Calculator is a practical tool designed to quickly compute the Coefficient of Performance (COP) and Energy Efficiency Ratio (EER) for heating and cooling systems. Whether you are evaluating a heat pump, air conditioner, or refrigeration unit, this calculator helps you determine efficiency ratings based on power input and output.
What the COP EER Calculator Does and When to Use It
The COP EER Calculator takes two key inputs: the useful thermal power output (in kilowatts) and the electrical power input (in kilowatts). It then calculates the COP value, which is equivalent to the EER for cooling systems, and assigns an efficiency class from A+++ (best) to B (lowest). It also estimates the percentage savings compared to a standard electric resistance heater.
You should use this calculator whenever you need to compare the energy performance of HVAC systems, verify manufacturer claims, or assess the efficiency of an existing installation. It is especially useful for:
- Sizing or evaluating heat pumps for residential or commercial buildings.
- Comparing different air conditioning units before purchase.
- Checking if a system meets minimum efficiency standards.
- Calculating potential energy cost savings versus conventional heating.
The Formula Explained Variable by Variable
The calculator uses a straightforward ratio based on thermodynamics. The core calculation is:
COP = Useful Thermal Power Output (kW) ÷ Electrical Power Input (kW)
For cooling systems, the same value represents the EER. Let us break down each variable:
| Variable | Description | Unit |
|---|---|---|
| Qu (potencia_util_kw) | Useful heating or cooling power delivered by the system. For heat pumps, this is the heat transferred; for air conditioners, it is the cooling capacity. | Kilowatts (kW) — approximately 3412 BTU/h per kW |
| Qe (potencia_elec_kw) | Electrical power consumed by the compressor and fans to produce that heating or cooling effect. Includes all active power input. | Kilowatts (kW) — 1 kW ≈ 1.341 horsepower |
| COP | Ratio of useful output to electrical input. A COP of 3.0 means for every 1 kW of electricity, 3 kW of heat (or cooling) is produced. | Dimensionless |
| EER | Equal to COP for this calculator, but typically expressed in BTU/h per watt in the US. Here it directly mirrors the COP value. | Dimensionless |
| Clase de eficiencia | Efficiency class based on COP: A+++ (≥5.0), A++ (≥4.0), A+ (≥3.5), A (≥3.0), B (<3.0). | Letter grade from A+++ to B |
| Ahorro vs resistencia | Percentage savings compared to a standard electric resistance heater (which has a COP of 1.0). Calculated as (1 - 1/COP) × 100%. | Percentage (%) |
Two Worked Examples with Concrete Numbers
Example 1: High-Efficiency Heat Pump (Heating Mode)
A modern air-source heat pump delivers 4.5 kW of heat while drawing 1.2 kW of electricity.
- Useful power (Qu): 4.5 kW
- Electrical power (Qe): 1.2 kW
- COP calculation: 4.5 ÷ 1.2 = 3.75
- EER: 3.75 (same value)
- Efficiency class: A+ (since 3.5 ≤ 3.75 < 4.0)
- Savings vs resistance heater: (1 - 1/3.75) × 100% = (1 - 0.267) × 100% = 73.3%
This means the heat pump uses 73.3% less electricity than a conventional electric heater to produce the same amount of heat. In practical terms, for every $100 spent on electric heating, this system would cost only about $26.70 to run.
Example 2: Window Air Conditioner (Cooling Mode)
A small window unit has a cooling capacity of 2.6 kW (approximately 8,870 BTU/h) and consumes 0.85 kW of electricity.
- Useful power (Qu): 2.6 kW
- Electrical power (Qe): 0.85 kW
- COP/EER calculation: 2.6 ÷ 0.85 = 3.06
- Efficiency class: A (since 3.0 ≤ 3.06 < 3.5)
- Savings vs resistance heater: (1 - 1/3.06) × 100% = (1 - 0.327) × 100% = 67.3%
Although this unit is less efficient than the heat pump in Example 1, it still achieves a 67.3% energy saving compared to a resistive electric heater. The EER of 3.06 corresponds to approximately 10.4 BTU/h per watt (since 3.06 × 3.412 = 10.44), which is a decent rating for a standard window AC.
Common Mistakes to Avoid
Getting accurate results from the COP EER Calculator requires careful attention to the inputs. Here are the most frequent errors:
- Mixing up power units: Always enter both values in kilowatts. If your system is rated in BTU/h, divide by 3,412 to convert to kW. For horsepower, multiply by 0.746 to get kW.
- Using input power instead of output power: The useful power (Qu) must be the thermal output (heating or cooling capacity), not the electrical input. Confusing these two will give a COP near 1.0, which is incorrect for efficient systems.
- Neglecting auxiliary power: For heat pumps, ensure the electrical input includes all components (compressor, fan motors, defrost cycle heaters if applicable). Excluding these gives an artificially high COP.
- Assuming COP and EER are always interchangeable: While this calculator treats them as identical for simplicity, in professional contexts EER for cooling is sometimes measured in BTU/h per watt. The numeric value differs. Always check which definition applies to your system.
- Applying the savings percentage incorrectly: The savings shown are relative to a resistance heater (COP = 1.0). If comparing to a gas furnace or another heat pump, the savings will be different.
Frequently Asked Questions
What is the difference between COP and EER?
In this calculator, COP and EER are given the same numeric value because both represent a ratio of useful output to electrical input. However, in the HVAC industry, EER is often expressed in BTU/h per watt for cooling systems. To convert from the dimensionless COP to BTU/h per watt, multiply by 3.412. For example, a COP of 3.75 equals an EER of 12.8 BTU/h per watt (3.75 × 3.412 ≈ 12.8). For heating, only COP is used.
What is a good COP for a heat pump?
Modern air-source heat pumps typically achieve COPs between 2.5 and 4.5 depending on outdoor temperatures. Ground-source (geothermal) heat pumps can reach COPs of 4.0 to 6.0 or higher. In our calculator, a class A+ (COP ≥ 3.5) is considered good, while A++ (COP ≥ 4.0) and A+++ (COP ≥ 5.0) represent excellent efficiency. Always check the manufacturer's data at your specific operating conditions.
Can I use this calculator for refrigeration systems?
Yes, the same principle applies. Refrigerators and freezers also have a COP defined as cooling capacity divided by electrical input. However, note that refrigeration COPs are often lower than heat pump COPs due to smaller temperature lifts. A typical household refrigerator may have a COP of 1.5 to 2.5. The efficiency classes (A+++ to B) are calibrated for heating systems, so they may not directly correspond to refrigeration standards. For refrigeration, focus on the raw COP value and the savings percentage.